2008-04-06から1日間の記事一覧
;;; Exercise 3.1 [m] Show a lambda expression that is equivalent to ;;; the above let* expression. You may need more than one lambda. (let* ((x 10) (y (+ x 20))) (list x y)) (funcall #'(lambda (x) (funcall #'(lambda (y) (list x y)) (+ x 20…